Solve this. Get a bOOm.
All leters hide an integers. No fraction numbers
several different leters do not refere to the same digit
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- A => A
- Which means BCD + ACD + CD <= 1000
- B + A = 4
- C + C + C = A
- D + D + D = ...?!!
Is that even a D?
...Wait, what?!!
Because it cantelope.
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A & B are 2, C is 0, D is 8; therefore
ABCD (2208)
+ACD (208)
.....CD (08)
is 2424
3D need to end up in 4, thus D=8
A and B are small numbers (from B A -> 4) lower than 4. Considering also C C C -> A it means that A can be max 3.
From here on I did some error and try and got to A=1, B=2, C=3, D=8